Question

IX. At what angle the max. height and range of projectile are equal?

Name: IX. At what angle the max. height and range of projectile are equal?
Uploaded: 2019-06-12T21:56:59-08:00
Duration: 7 min 58 s
Channel: Zachary Warner
Description: IX. At what angle the max. height and range of projectile are equal?

          IX. At what angle the max. height and range of projectile are equal?

Added by Brian H.

Physics for Scientists and Engineers with Modern Physics

Douglas C. Giancoli 4th Edition

Chapter 3

Instant Answer

Solved by Expert Zachary Warner

06/12/2019

Step 1

- Maximum height (\(H\)) is given by: \[ H = \frac{v_0^2 \sin^2 \theta}{2g} \] - Range (\(R\)) is given by: \[ R = \frac{v_0^2 \sin 2\theta}{g} \] where \(v_0\) is the initial velocity, \(\theta\) is the angle of projection, and \(g\) is the acceleration Show more…

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