00:01
To draw the lewis structure, we first need to count the number of valence electrons.
00:06
Sulfur has six valence electrons, oxygen has six.
00:10
Chlorine has seven, and there's two of them.
00:13
So that gives us a total of 26 valence electrons.
00:19
If we put sulfur in the middle and we bond each chlorine and bond the oxygen, we would have used up six of the 26.
00:29
If we add three lone pairs to the chlorine, we would have used up 12.
00:37
If we add three lone pairs to oxygen.
00:45
We've now used a total of 24.
00:47
And so we've got two more left that we can put on sulfur.
00:53
As suggested, we need to double bond the oxygen to sulfur, sulfur achieving an expanded octet.
01:02
The oxidation state with this lewis structure on oxygen, becomes zero.
01:08
Oxygen has six valence electrons and it has one, two, three, four, five, six assigned to it.
01:15
Sulfur has six valence electrons and it has one, two, three, four, five, six assigned to it...