(j) Calculate: (i) the carrier concentration, and (ii) the proportion of current carried by holes in an intrinsic Ge crystal at 300 K which has a conductivity of 2.0 -1m-1. Assume n 0.38 and p 0.18 m2V-1s-1.
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Step 1
0 Ω⁻¹ m⁻¹, q = 1.6 × 10⁻¹⁹ C, μn = 0.38 m² V⁻¹ s⁻¹, μp = 0.18 m² V⁻¹ s⁻¹. μn + μp = 0.56 m² V⁻¹ s⁻¹ ni = σ / [q (μn + μp)] = 2.0 / [1.6×10⁻¹⁹ × 0.56] ≈ 2.2 × 10¹⁹ m⁻³. Show more…
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