Jacky exerts a force of 6.64 x 102 dN on the end of a door 8.45 x 102 mm wide. What is the magnitude of the torque if the force is exerted perpendicular to the door.
Added by Anele Z.
Step 1
1 dN (decanewton) = 10 N (newton) 1 mm (millimeter) = 0.001 m (meter) So, the force Jacky exerts is 6.64 x 102 dN = 6.64 x 102 x 10 N = 6.64 x 103 N. The width of the door is 8.45 x 102 mm = 8.45 x 102 x 0.001 m = 8.45 x 10 m. The torque (τ) is calculated by Show more…
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