Question

Java Python List-1 > first_last6 prev | next | chance Given an array of ints, return True if 6 appears as either the first or last element in the array. The array will be length 1 or more. first_last6([1, 2, 6]) ? True first_last6([6, 1, 2, 3]) ? True first_last6([13, 6, 1, 2, 3]) ? False Go ...Save, Compile, Run (ctrl-enter) Show Hint def first_last6(nums):

          Java
Python
List-1 > first_last6
prev | next | chance
Given an array of ints, return True if 6 appears as either the first or last element in the
array. The array will be length 1 or more.
first_last6([1, 2, 6]) ? True
first_last6([6, 1, 2, 3]) ? True
first_last6([13, 6, 1, 2, 3]) ? False
Go
...Save, Compile, Run (ctrl-enter)
Show Hint
def first_last6(nums):

Java
Python
List-1 > firstlast6
prev | next | chance
Given an array of ints, return True if 6 appears as either the first or last element in the
array. The array will be length 1 or more.
firstlast6([1, 2, 6]) ? True
firstlast6([6, 1, 2, 3]) ? True
firstlast6([13, 6, 1, 2, 3]) ? False
Go
...Save, Compile, Run (ctrl-enter)
Show Hint
def firstlast6(nums):

Added by Catherine J.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Madhur L

08/16/2023

Step 1

def first_last6(nums): if len(nums) == 1: return True Show more…

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Thanks for your feedback!

Java Python List-1 > first_last6 Given an array of ints, return True if 6 appears as either the first or last element in the array. The array will be length 1 or more. first_last6([1, 2, 6]) → True first_last6([6, 1, 2, 3]) → True first_last6([13, 6, 1, 2, 3]) → False def first_last6(nums):