Question

class Caller { private void init() { System.out.println("Initialized"); } protected void start() { init(); System.out.println("Started"); } } public class TestCall { public static void main(String[] args) { Caller c = new Caller(); c.start(); // line n1 c.init(); // line n2 } } What is the result? O A) Initialized Started Initialized O B) Compilation fails at line n2. O C) Compilation fails at line n1. O D) Initialized Started

          class Caller {
private void init() {
System.out.println("Initialized");
}
protected void start() {
init();
System.out.println("Started");
}
}
public class TestCall {
public static void main(String[] args) {
Caller c = new Caller();
c.start(); // line n1
c.init(); // line n2
}
}
What is the result?
O A) Initialized
Started
Initialized
O B) Compilation fails at line n2.
O C) Compilation fails at line n1.
O D) Initialized
Started

class Caller
private void init()
System.out.println("Initialized");

protected void start()
init();
System.out.println("Started");

public class TestCall
public static void main(String[] args)
Caller c = new Caller();
c.start(); // line n1
c.init(); // line n2

What is the result?
O A) Initialized
Started
Initialized
O B) Compilation fails at line n2.
O C) Compilation fails at line n1.
O D) Initialized
Started

Added by David B.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Florencia Cuzmar

Step 1

The `init()` method is private, which means it can only be accessed within the `Caller` class. The `start()` method is protected, which means it can be accessed within the `Caller` class and any subclasses, but not from other classes. Show more…

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Thanks for your feedback!

```java class Caller { private void init() { System.out.println("Initialized"); } protected void start() { init(); System.out.println("started"); } } public class TestCall { public static void main(String[] args) { Caller c = new Caller(); c.start(); // line n1 c.init(); // line n2 } } ```