Question

7. JM = \sqrt{12} and ML = \sqrt{20}. Leave your answer as an exact radical, not as a decimal. a) Find the area of \triangle JKL. b) Find the perimeter of \triangle JKL.

          7. JM = \sqrt{12} and ML = \sqrt{20}. Leave your
answer as an exact radical, not as a decimal.
a) Find the area of \triangle JKL.
b) Find the perimeter of \triangle JKL.

7. JM = √(12) and ML = √(20). Leave your
answer as an exact radical, not as a decimal.
a) Find the area of JKL.
b) Find the perimeter of JKL.

Added by Kristen J.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Jonathon Brumley

Step 1

Since JM = M1Z, we can say that JM = MZ. This means that triangle JMK is an isosceles triangle. Similarly, since ML = v2O, we can say that ML = LO. This means that triangle LMO is also an isosceles triangle. Since JMK is an isosceles triangle, we can say that Show more…

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