John weighs 76 kg and following his warm up he exercises at...

John weighs 76 kg and following his warm-up, he exercises at 10.5 METs on a treadmill at Red Lerille’s Health Club. He was recently given a Monark stationary leg bike and he wants to exercise at the same workload as the treadmill; however, he doesn’t know what resistance setting or RPMs he should use. If you prescribed 70 RPMs as the pedaling rate, what would the resistance setting have to be to obtain a 10.5 MET workload? Round the answer to the nearest whole kg.

Transcript

00:01 In this question we have been given the male weight male weight is equal to 210 pound and with the vo2 max of 41 we have vo2 max of 41 of 41 ml per k g per k g minute and the target vo2 to be achieved is given to us so target v -o -2 to be achieved with 75 % of v -o -2 max so if we calculate it here it would be 75 over 100 of vot max is 41 so it comes out to be 30 .75m.

01:01 Ml over kg minute.

01:06 Since and we are given the pedal revolution of 70 rpm so we have to find what resistance would we have to work against in order to achieve this intensity and also how fast would this individual have to run on the level surface to achieve this same intensity.

01:24 Now we know that we know that vo2 at vo2 at monarch, bicycle, ergo meter is given by v -o -2 is given by target is equal to 1 .8 times work rate over body mass, body mass plus 7 .7.

02:10 Here if we put the value so we have to target vot is 30 .75 that was 75 % of maximum is equal to 1 .8 times work rate over the body mass is given so we have to convert it and it was in pound so when we convert it into kg it is 95 .25 plus 7 so the work rate work rate is found out to be 1 to 56 .77 k g per meter per minute now we have to find the resistance here we are given we know a formula that is work rate work rate is equal to resistance resistance multiplied with multiple with with here the width d multiplied by the pedal pedal cadence pedal cadence so here when we put the values so work rate is known to us so 1256 .77 is equal to resistance setting we have to find out so resistance multiplied by 6 multiplied me 70 so here resistance is equal to 2 .99 kg.

03:55 This is a restriction.

03:56 He had to work against to achieve 75 % of the intensity.

04:01 Now we have to find out that how fast would this individual have to run on a level surface to achieve this same intensity...

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