The binomial theorem states that (a + b)^n = C(n,0)a^n b^0 + C(n,1)a^(n-1) b^1 + C(n,2)a^(n-2) b^2 + ... + C(n,n-1)a^1 b^(n-1) + C(n,n)a^0 b^n
In this case, a = x^2, b = 2x, and n = 10.
So, the expansion becomes:
(x^2 + 2x + 1)^10 = C(10,0)(x^2)^10 (2x)^0 +
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