00:01
So the maximum height of the ball goes above the ground can be calculated using the kinematic equation of motions.
00:08
So here we use the rule h equals vii into t minus 0 .5 into g into t square.
00:20
So here vii is the initial velocity.
00:26
Vii equals 20 into sine.
00:30
The given angle is 54 degrees so it will be 15 .96 meter per second and time to reach it is v i y by g so it is nothing but 15 .96 by 9 .8 we get 1 .62 seconds and acceleration due to gravity g is 9 .8 so substituting this values in our above given equation we get h equals 15 .96 in into 1 .62 minus 0 .5 into 9 .8 into 1 .62 square, which will give us the answer of h as 20 .18 meter.
01:15
So this is our height.
01:17
The ball goes above the ground in 20 .18 meters.
01:21
And the next part to calculate the distance between two girls, we need to consider the horizontal component of the initial velocity and the time t.
01:30
So the horizontal component of the initial velocity is given by v ix equals 20 into cost.
01:41
The given theta is 54.
01:44
So this is nothing but 15 .4 meter per second.
01:51
So the time taken is the formula is d equals v ix into t.
01:58
So if we substitute the values, you get 15 .4.
02:01
Into 1 .62...