Question

3. (20 points) For the characteristic equation $1 + \frac{K}{s(s+1)(s+5)} = 0$, (1). (5 points) Draw the real-axis segments of the corresponding root locus. (2). (5 points) Find the center and angle of the asymptotes of the locus for $K \to \infty$. (3). (5 points) Find the break-away point and the imaginary crossing point. (4). (5 points) Sketch the locus.

          3. (20 points) For the characteristic equation $1 + \frac{K}{s(s+1)(s+5)} = 0$,
(1). (5 points) Draw the real-axis segments of the corresponding root locus.
(2). (5 points) Find the center and angle of the asymptotes of the locus for $K \to \infty$.
(3). (5 points) Find the break-away point and the imaginary crossing point.
(4). (5 points) Sketch the locus.

3. (20 points) For the characteristic equation 1 + (K)/(s(s+1)(s+5)) = 0,
(1). (5 points) Draw the real-axis segments of the corresponding root locus.
(2). (5 points) Find the center and angle of the asymptotes of the locus for K →∞.
(3). (5 points) Find the break-away point and the imaginary crossing point.
(4). (5 points) Sketch the locus.

Added by Gabriel C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Pritesh Ranjan

Step 1

(2) To find the center and angle of the asymptotes, we can use the formula: angle = (2n + 1) * 180 / N where n is the index of the asymptote (starting from 0) and N is the total number of poles and zeros. The center of the asymptotes is given by Show more…

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(1) Draw the real-axis segments of the corresponding root locus. (2) Find the center and angle of the asymptotes of the locus for K. (3) Find the break-away point and the imaginary crossing point. (4) Sketch the locus.