Question

3. [4 pts] In the position and rate feedback system of Figure 2, let bm = 280 and am = 40. Determine the values of $K_{pe}$ and $K_d$ for which the feedback system has 18% overshoot and $T_s$ = 2 sec. What will the SSE to a unit step input be?

          3. [4 pts] In the position and rate feedback system of Figure 2, let bm = 280 and am = 40.
Determine the values of $K_{pe}$ and $K_d$ for which the feedback system has 18% overshoot and $T_s$ = 
2 sec. What will the SSE to a unit step input be?

3. [4 pts] In the position and rate feedback system of Figure 2, let bm = 280 and am = 40.
Determine the values of Kpe and Kd for which the feedback system has 18% overshoot and $Ts$ =
2 sec. What will the SSE to a unit step input be?

Added by Silvia H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kamlesh Goyal

Step 1

The formula for overshoot is given by: Overshoot = exp((-ζπ) / sqrt(1 - ζ^2)) * 100 Rearranging the formula, we can solve for ζ: ζ = sqrt((log(overshoot/100))^2 / (π^2 + (log(overshoot/100))^2)) Plugging in the given overshoot of 18%, we get: ζ = Show more…

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Kd = 0.129, Kpe = 0.062. Show steps. 3. [4 pts] In the position and rate feedback system of Figure 2, let bm = 280 and am = 40. Determine the values of Kpe and Ka for which the feedback system has 18% overshoot and Ts = 2 sec. What will the SSE to a unit step input be? bm s + am 1 S position (rad) command input motor voltage (V) speed (rad/sec) Step Gain Transfer Fcn Integrator Gain1 Derivative