Question

KINETICS AND EQUILIBRIUM - Calculating equilibrium composition from an equilibrium constant Suppose a 250 mL flask is filled with 1.1 mol of Cl2, 1.3 mol of CHCl3, and 1.6 mol of HCl. The following reaction becomes possible: Cl2(g) + CHCl3(g) + HCl(g) -> CCl4(g) The equilibrium constant K for this reaction is 0.714 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.

Name: kinetics and equilibrium calculating equilibrium composition from an equilibrium constant suppose a 250ml flask is filled with 11mol of cl2 13mol of chcl3 and 16mol of hclthe following react 98623
Uploaded: 2022-06-15T08:54:10-08:00
Duration: 5 min 3 s
Channel: Shaiju T
Description: kinetics and equilibrium calculating equilibrium composition from an equilibrium constant suppose a 250ml flask is filled with 11mol of cl2 13mol of chcl3 and 16mol of hclthe following react 98623

          KINETICS AND EQUILIBRIUM - Calculating equilibrium composition from an equilibrium constant

Suppose a 250 mL flask is filled with 1.1 mol of Cl2, 1.3 mol of CHCl3, and 1.6 mol of HCl. The following reaction becomes possible:
Cl2(g) + CHCl3(g) + HCl(g) -> CCl4(g)

The equilibrium constant K for this reaction is 0.714 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.

Added by Jonathan L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Shaiju T

06/15/2022

Step 1

Step 1: Write the equilibrium constant expression for the reaction: \[ K = \frac{[CCl_4]}{[Cl_2][CHCl_3]} \] Show more…

Show all steps

Thanks for your feedback!

KINETICS AND EQUILIBRIUM - Calculating equilibrium composition from an equilibrium constant Suppose a 250 mL flask is filled with 1.1 mol of Cl2, 1.3 mol of CHCl3, and 1.6 mol of HCl. The following reaction becomes possible: Cl2(g) + CHCl3(g) + HCl(g) -> CCl4(g) The equilibrium constant K for this reaction is 0.714 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.