00:01
We are asked to find the solubility of copper 1 bromide in a, pure water, and b, in 0 .003 molar solution of cobalt bromide.
00:12
Okay, so let's do this, i guess, for both of them.
00:25
My ksp expression will be the simple one.
00:37
This will be s squared.
00:40
So for my solubility for this in pure water, let me see, 10 to the minus 9th.
01:03
And let's do this.
01:05
Second square root 6 .5 times equals 8 .06, 8 .1 times 10 to the minus fifth molar.
01:17
Let me go check my problem.
01:23
They want grams per liter.
01:29
So 8 .062 moles per liter times times 143 .45 grams per mole.
01:53
Remember, in my calculator, this is times 10 to the 5th.
02:14
Times 143 .45 equals 0 .012 grams per liter.
02:32
Okay, so the answer you're supposed to enter should be 0 .01.
02:42
Round your answer to two sigmics.
02:44
Okay, so i want to make a note here...