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Hello students, we are given the following figure.
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Using this figure we need to find out the sum of the voltages in the loops that are being asked.
00:15
First, we need to consider the loop a, b, c, d, f, g, h, a, that is the entire outer loop.
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Thus, in the loop, a, b, c, d, c d, efgha using the kirchof's circuital law.
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We will have, starting from a, the voltage will be the current i1 multiplied by resistance r1.
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Then moving on after b, the negative terminal of e1 is facing first.
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So we will write minus e1.
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Then we have the internal distance r1 of e1.
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So the voltage will be plus i1 into r1.
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Then moving on from d to e there is no component.
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After e we have the resistance r3.
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However, the current i3 is flowing in the opposite direction to our clockwise direction of the loop.
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As we will put here a negative sign, we will have minus i3 into the resistance r3.
01:23
Moving on from f we have the internal resistance r2 and again the i3 is an opposite...