00:01
Let me take notes the given values here.
00:02
So the sample size denoted by n which is 36 and the sample mean is also given here which is 3 ,150 gram and the standard division for the sample which is given as 695 .5 and the confidence level which is given as 99 percent which can be written as 0 .99.
00:23
So we're gonna find the confidence interval.
00:26
First of all i'm gonna find the t alpha over 2 value.
00:32
First of all i need to get the alpha value which is 1 minus confidence level.
00:36
So i need alpha over 2, 1 minus 0 .99 and divide by 2 which would be 0 .005.
00:42
So and also i need the degrees of freedom n minus 1, 36 minus 1 which is 35.
00:49
To get the t value i'm gonna use the inverse t function.
00:53
So the area was 0 .005 and the degrees of freedom is 35.
00:58
Press second variance and the inverse t this is 0 .005 and the 35 here so the value would be negative 2 .72 and 4.
01:09
So this is the t value we have.
01:12
And the b we have to find the margin of error.
01:15
So the margin of error which is t alpha over 2 times sample standard division divided by root n...