Question

Knight Exercise/Problem 27.49: The resistivity of a metal increases slightly with increased temperature. This can be expressed as ρ = ρ0 [1 + α (T − T0)], where T0 is a reference temperature, usually 20◦C, and α is the temperature coefficient of resistivity. For copper, α = 3.9 × 10−3◦C−1. Suppose a long, thin copper wire has a resistance of 0.25Ω at 20◦C. At what temperature, in ◦C, will its resistance be 0.30Ω ?

Name: knight exerciseproblem 2749 the resistivity of a metal increases slightly with increased temperature this can be expressed as 0 1 t t0 where t0 is a reference temperature usually 20c and is 23245
Uploaded: 2022-05-03T10:02:18-08:00
Duration: 2 min 40 s
Channel: Sikandar Baig
Description: knight exerciseproblem 2749 the resistivity of a metal increases slightly with increased temperature this can be expressed as 0 1 t t0 where t0 is a reference temperature usually 20c and is 23245

          Knight Exercise/Problem 27.49:
The resistivity of a metal increases slightly with increased temperature. This can be expressed
as ρ = ρ0 [1 + α (T − T0)], where T0 is a reference temperature, usually 20◦C, and α is the
temperature coefficient of resistivity. For copper, α = 3.9 × 10−3◦C−1. Suppose a long, thin
copper wire has a resistance of 0.25Ω at 20◦C. At what temperature, in ◦C, will its resistance
be 0.30Ω ?

Added by Elena C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sikandar Baig

05/03/2022

Step 1

The resistivity of the metal is given by: \[ \rho = \rho_0 [1 + \alpha (T - T_0)] \] where \( \rho_0 \) is the resistivity at the reference temperature \( T_0 \), \( \alpha \) is the temperature coefficient of resistivity, and \( T \) is the temperature in °C. Show more…

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Knight Exercise/Problem 27.49: The resistivity of a metal increases slightly with increased temperature. This can be expressed as ρ = ρ0 [1 + α (T − T0)], where T0 is a reference temperature, usually 20◦C, and α is the temperature coefficient of resistivity. For copper, α = 3.9 × 10−3◦C−1. Suppose a long, thin copper wire has a resistance of 0.25Ω at 20◦C. At what temperature, in ◦C, will its resistance be 0.30Ω ?