00:01
Hello everyone here it is given in the question that the clamp is so and p is equal to here given as 400 newton now we have to find the stress at point a and b number a stress at point b d sorry yeah now c party is here location of neutral access so let's start so coming to the solution part here we all here know that bending couple that is f is equal to p multiplied by e now here we'll find the e right so let's come e is equal to here is so this is 50 plus 20 minus 11 .85, right? so here e is coming out to be 58 .15.
01:22
Now, going further here, we'll find the moment of inertia.
01:25
So this is here, i is equal to i1 plus, right? and d1 is here 18 minus 11 .8.
01:37
So we can write i1 as b d q over 12 plus a1 d1 square right so here this is coming out of of the 10 multiplied by 4 cube over 12 plus 40 multiplied by 18 minus 11 .8 5 4 square right so this is coming out of 566 .23 m m x to power 4 right right now, for portion 2, we'll find the value of i2.
02:11
I2 is bdq over 12 plus a2, d2, right? now here, d2 is equal to 3 .85m, right? now, this is 4 multiplied 16 q over 1 plus a2.
02:32
This is 64 multiplied by 3 .85 so this is coming out to be here 202313 .973 m m raised to power 4 right now here i is coming out to i1 plus i2 so this is here 3880 .203 multiplied by 10 x4 minus 202.
03:04
Going further here we have to find the stress so this is stress at a is equal to stress centric plus the stress and so and this is here and this is here p over a plus p e now p, this is 4 .10 over 8, 1 1025, 1010 .6 plus p multiplied by e, 0 .058, and that is multiplied in c.
03:45
So this is 0, 0, 0, 0, 5...