Kp = 0.0198 at 721 K for the reaction 2HI (g) H2 (g) + I2 (g) In a particular experiment, the partial pressures of H2 and I2 at equilibrium are 0.664 and 0.796 atm, respectively. The partial pressure of HI is ________ atm.
Added by Scott G.
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The reaction is: \[2HI(g) \rightleftharpoons H_2(g) + I_2(g)\] And the equilibrium constant, \(K_p\), is given as 0.0198 at 721 K. Show more…
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