00:01
So in this question, values of relative rate, values of relative rate as well as temperature.
00:11
So values of relative rate and temperature and temperature they have given.
00:17
So now we have to calculate logarithm of relative rate and 1 by temperature.
00:28
So, logarithm of 2 .29 is equal to 0 .826.
00:36
Whereas logarithm of 2 .91 value it is 1 .068.
00:42
Logarithm of 7 .29, that is 1 .9865.
00:48
Logarithm of 24 .39, 3 .1942.
00:55
So, in order to calculate 1 by t, so here we have to calculate 1 by 10.
01:02
So 1 by t that is 1 by 708 kelvin's that is 0 .00141 kelvin whereas 1 by 616 kelvin that is 0 .00162 kelvin inverse whereas 1 by 410 that is 0 .002 -44 kelvin inverse whereas 1 by 410 that is 0 .002 44 kelvin inverse whereas 1 by 3 that is 0 .00318 kelvin inverse...