Question

Ksp for Pbl2(s) = 1.4 \times 10^{-8}. What mass of Pbl2(s) (461 g/mol) can dissolve in 51.7 L of 0.30 M KI solution? Provide answer in milligrams (mg) to 2 significant figures.

          Ksp for Pbl2(s) = 1.4 \times 10^{-8}. What mass of Pbl2(s) (461 g/mol) can dissolve in 51.7 L of 0.30 M KI solution? Provide answer in milligrams (mg) to 2 significant figures.
        
Ksp for Pbl2(s) = 1.4 Ă—10^-8. What mass of Pbl2(s) (461 g/mol) can dissolve in 51.7 L of 0.30 M KI solution? Provide answer in milligrams (mg) to 2 significant figures.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Ksp for PbI2 = 1.4 x 10^-8. What mass of PbI2 (461 g/mol) can dissolve in 51.7 L of 0.30 M KI solution? Provide answer in milligrams (mg) to 2 significant figures.
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Transcript

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00:01 First we'll write the ksp reaction.
00:03 We have pbi2 as a solid dissociating into pb2 plus and two iodides.
00:15 So ksp is going to be equal to the concentration of pb2 plus multiplied by the concentration of iodide squared.
00:27 And they tell us this value is 1 .4 times 10 to the negative 8.
00:33 So to calculate the molar solubility we recognize that when one mole of the solid dissolves in a liter of solution we get one mole of lead 2 plus in a liter of solution...
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