Ksp of barium fluoride, BaF2 is 1.0 x 10^-6. Calculate its solubility in grams per liter, knowing that BaF2 has a molar mass of 208.23 g/mol:
BaF2 (s) ā Ba^2+ (aq) + 2F^- (aq)
Ksp = [Ba^2+][F^-]^2
1.0 x 10^-6 = (x)(2x)^2
1.0 x 10^-6 = 4x^3
x^3 = 2.5 x 10^-7
x = (2.5 x 10^-7)^(1/3)
x ā 6.3 x 10^-3 g/L