From the given equation $y^3 = 5x$, we have $x = \frac{y^3}{5}$.
The length $L$ is given as 28 mm. This means that when $x = L = 28$, we can find the corresponding $y$ value.
$y^3 = 5x = 5(28) = 140$, so $y = \sqrt[3]{140} \approx 5.1925$
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