00:01
Hi, here for the given question we are given this diagram.
00:04
Now here further in order to start with we want to draw a free body diagram of the beam for a point a as a support while point c is used as a string.
00:17
This is used as a string and here point a has a support point.
00:21
So here now taking the counterclockwise direction as a positive here we can see that sum of ma is equal to 0 to 5 0 2 into 1 plus 500 into 2 minus fc multiplied with 3 by 5 into 4 minus fc multiplied with 4 by 5 into 0.
00:47
So here this is equal to 625 newton.
00:50
So here this is the value of total ma.
00:54
Now this is the total value of sum of moments.
00:57
Now further the force acting along the x -axis will be equal to 0 into ax minus fc multiplied with 4 upon 5 which is equal to 0 ax minus 625 multiplied with 4 by 5.
01:13
So here in our case this is equal to 500 newton.
01:16
Now further fi can be calculated as 0 multiplied with ay plus fc multiplied with 3 by 5 minus 250 multiplied with 2 minus 500.
01:29
So here by calculating this value we can say that here in our case we have value of fi is equal to 625 newton here also.
01:39
So here now further in order to do the shear diagram here we can consider the shear forces at each point.
01:49
So here now further we can say that here we have va is equal to 0 newton va.
01:56
So again we have va plus va dash this is va dash multiplied with ay...