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Hello, my name is david.
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In this video, we'll cover the distribution normal and the distribution muestral of the media.
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For the problem number one, we're an average of 80 and a deviation standard of 10.
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And for the part a, we're going to find the probability of that the muestra is at minus 75 or major -ke or equal to 75.
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So, for this, we're going to use the application normal cdf of your calculator, where we have to put the limit inferior, the limit major, the media, and the deviation standard.
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So for this problem, our limit minimum is going to be 75 because we're including.
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The limit of major could be infinity or we can put 9 ,99, any number grand, the media, and the deviation standard.
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So when we put in the calculator, we've got we found that the probability that the moucester is equal to 75 is equal to 0 .69, 14 .6 and this is the result with five figures significantes.
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It can't redonear as the piddmasro.
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Now, for the part b, we take a muestra of 25, what which means that we have to find the deviation standard of the muestra, which is by the formula of the deviation standard divided by the radius quadrida of the moucrast then we're 10 divided by the radius quarter of 25 that is 10 between 5 that we for the part b we want to find that the mues that's major to 75 so no include 75 so when we use the function normal cdf or cdf we'll put the limit inferior, that is 75 .5, because we don't we're not including 75, the limit superior, which is infinity, or 9 ,199.
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Then the media, that is 80, and the deviation standard of the muestra, which is 2.
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So when we put us in the calculator, we've got the probability of that the muster be a more than 75 is .98 7 -78.
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And that is with five figures significant.
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And, another way, it can't redonear as you pida.
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Now, for the problem number two, we'll give a media of 50 and a deviation standard of 12.
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And we need for the part of a, that we'll find out that the probability of that the mustra is at least 45, which means that the must have to be major or equal to 45.
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Then we'll use again the function normal cdf where we put them the limit inferior which is 45 because we're including the limit major that is infinity or 999, any number large, the media that is 50, the deviation standard that is 12, and we've got that the probability that the mostra that is more than 45 is in 0 .66 154.
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Okay, for the part b, we take a moucrast a 16, what means that we need to find the deviation standard of the muestra, which is the deviation standard divided by the rarice quadrada of the muestra.
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So, we have 12 divided by the rarice quarada of 16, which is 12 divided into 4, that we're a 3...