Question

LAB XI. DETERMINING THE MOLARITY OF VINEGAR - The molar concentration of acetic acid (CH3COOH) in a vinegar sample can be determined by reacting the sample with a standardized solution of NaOH. The reaction of acetic acid with NaOH is: CH3COOH + NaOH -> NaCH3COO + H2O - A known volume of vinegar solution is titrated with standardized NaOH. - From the titration curve of this reaction, the equivalence point is determined. (The equivalence point is the midpoint of the steep portion of the titration curve). TITRATING VINEGAR Perform the calculations below to determine the concentration of acetic acid using a 0.15 M solution of NaOH. Write down how many moles of NaOH and moles of acetic acid there are in each problem. a. 62 mL of vinegar to neutralized 85 mL of NaOH. b. 68 mL of vinegar to neutralized 100 mL of NaOH. c. 170 mL of vinegar to neutralized 350 mL of NaOH. d. 0.87 mL of vinegar to neutralized 295 mL of NaOH. e. 450 mL of vinegar to neutralized 278 mL of NaOH.

          LAB XI. DETERMINING THE MOLARITY OF VINEGAR

- The molar concentration of acetic acid (CH3COOH) in a vinegar sample can be determined by reacting the sample with a standardized solution of NaOH. The reaction of acetic acid with NaOH is:
CH3COOH + NaOH -> NaCH3COO + H2O
- A known volume of vinegar solution is titrated with standardized NaOH.
- From the titration curve of this reaction, the equivalence point is determined. (The equivalence point is the midpoint of the steep portion of the titration curve).

TITRATING VINEGAR

Perform the calculations below to determine the concentration of acetic acid using a 0.15 M solution of NaOH. Write down how many moles of NaOH and moles of acetic acid there are in each problem.

a. 62 mL of vinegar to neutralized 85 mL of NaOH.
b. 68 mL of vinegar to neutralized 100 mL of NaOH.
c. 170 mL of vinegar to neutralized 350 mL of NaOH.
d. 0.87 mL of vinegar to neutralized 295 mL of NaOH.
e. 450 mL of vinegar to neutralized 278 mL of NaOH.

LAB XI. DETERMINING THE MOLARITY OF VINEGAR

- The molar concentration of acetic acid (CH3COOH) in a vinegar sample can be determined by reacting the sample with a standardized solution of NaOH. The reaction of acetic acid with NaOH is:
CH3COOH + NaOH -> NaCH3COO + H2O
- A known volume of vinegar solution is titrated with standardized NaOH.
- From the titration curve of this reaction, the equivalence point is determined. (The equivalence point is the midpoint of the steep portion of the titration curve).

TITRATING VINEGAR

Perform the calculations below to determine the concentration of acetic acid using a 0.15 M solution of NaOH. Write down how many moles of NaOH and moles of acetic acid there are in each problem.

a. 62 mL of vinegar to neutralized 85 mL of NaOH.
b. 68 mL of vinegar to neutralized 100 mL of NaOH.
c. 170 mL of vinegar to neutralized 350 mL of NaOH.
d. 0.87 mL of vinegar to neutralized 295 mL of NaOH.
e. 450 mL of vinegar to neutralized 278 mL of NaOH.

Added by Emily L.

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