Using the trigonometric ratios in $\triangle BCD$, we have:
$\sin(\angle CBD) = \frac{CD}{BD}$
$\sin(34^\circ) = \frac{CD}{139}$
$CD = 139 \sin(34^\circ) \approx 139(0.559) \approx 77.7$
$\cos(\angle CBD) = \frac{BC}{BD}$
$\cos(34^\circ) = \frac{BC}{139}$
$BC =
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