00:01
We are given all of the following information.
00:03
We're given the molarity of our standardized sodium hydroxide.
00:07
We're told that the acid is hydrochloric.
00:10
I've written my balanced chemical equation so you can see all the mole ratios are one to one.
00:14
And we're given everything i've written in purple here.
00:18
So what we're going to calculate first is the volume of naoh which will be vf minus vi for each one of these trials.
00:29
Let me do this quickly.
00:30
23 .65 minus 5 .8.
00:37
Whoopsie i did that wrong.
00:38
I press times 23 .65 minus 5 .8 and that's 17 .85.
00:50
20 .55 minus 2 .65 is 17 .90 and 23 .8 minus 5 .75 is 18 .05.
01:10
Okay next our molarity we will get by recognizing first, well let me just write the whole calculation down here.
01:31
I'm going to do the following calculation for each one of these.
01:34
I'm going to take my volume of naoh in liters times my molarity which was 0 .0997 moles per liter times my one to one mole ratio naoh hcl and i guess i'll do this in milliliters so i can stick here...