00:01
Dear students, the lake contains 3 .9 billion liter of water which is acidulated by rainwater, acid rain, its ph is 5 .6.
00:09
We have to calculate mass of calcium carbonate required to neutralize it.
00:14
Now, here lake contains 3 .9 billion liter.
00:21
So 3 .9 billion liter equal to 3 .9 multiplied by 10 to 9 .9 liter.
00:31
Now, let us first calculate the hydrogen ion concentration.
00:37
Hydrogen ion concentration equal to 10 to the power minus ph equal to 10 to the power minus 5 .6 which is equal to 2 .5 multiplied by 10 to the power minus 6 molar.
00:51
So this is the hydrogenine concentration.
00:54
Then let us calculate this is molar means moles per liter.
00:59
Therefore, total number moles of hydrogen ion equal to in the entire lake.
01:09
That means how many moles of hydrogen ion is present, moles of hydrogen ion equal to in one letter it is 2 .5 multiplied by 10 to 06, multiplied by how many letters we are having? 3 .9 multiplied by 10 to the power 9 .9 .75 multiplied by 10 to 0 .03.
01:29
These are the moles of h plus ion present in the lake.
01:33
Now how calcium carbonate reacts? calcium carbonate reacts with h plus to give ca 2 plus co2 plus h2 so ca2 plus co2 plus h2.
01:54
It is balanced now.
01:55
That means 1 mole of calcium carbonate reacts 2 moles of h plus.
01:59
That means moles of carbon calcium carbonate required will be half of the moles of h plus n...