0:00
Hi there.
00:01
So for this problem, we need to use the result of the preceding problem to find the two wavelengths at which the function row of the, and function of the wavelength, has a value of one -half the value of the maximum wavelength.
00:22
So we need to give your answer in terms of the maximum wavelength.
00:28
Now, by problem 20, we know that the function row of d evaluated at the maximum wavelength is 170 times pi times boltzman constant times the temperature to the 5, and this divided by plams constant times the speed of light and that to the 4.
00:51
So that the wavelength must satisfy the following equation, that is, a times, pi times plants constant times the speed of light and this divided by the wavelength to the five times one over the exponential of plants constant times the speed of light and this divided by the wavelength times boltsman constant times the temperate were and this minus one so in here we can say that this is going to be equal to one over two remember that we need half of of the value 170 times pi times boltzmann constant times the temperature to the phi and this divided by plams constant times the speed of light to the four.
01:42
Again, we're gonna let that x is equal to plamps constant times the speed of light divided by the wavelength, boltzman constant, and the temperature...