00:01
Rates of heat flow in a road is given by q is equal to minus ka delta t by l, where k is the heat transfer coefficient, a is the area, delta t is the variation of temperature and l is the length of the material.
00:27
In the question we are given area a is equal to 8 .14 into 10 to 12 to 1 .12 into 10 to 2 meter square.
00:35
We have two roads, one is made of steel and the other made of aluminium alloy.
00:45
Steel road is kept at a temperature 0 degrees celsius at one end and let t be the temperature between the two roads and the other end of aluminium is at 100 degrees celsius.
00:59
Converting it into kelvin, this 273 kelvin and this is 373 kelvin.
01:08
And the heat transfer coefficient of steel, k is equal.
01:12
To 394 watt meter kelvin and for aluminum alloy ka is equal to 765 .8 watt per meter kelvin.
01:29
We are asked to find the equilibrium temperature between these roads.
01:34
Consider the fact that rate of heat transfer is uniform...