Question

1. A unidirectional lamina is under biaxial normal loading ?x = -2?y = 2?o at 45° to the fiber direction as shown below. The strength properties of the material are F1t = F1c = 3F2c = 5F6 = 12F2t = 600 MPa. Determine the stress level, ?o, at which the laminae will fail according to the maximum stress theory. What is the failure mode?

Name: 1. A unidirectional lamina is under biaxial normal loading ?x = -2?y = 2?o at 45° to the fiber direction as shown below. The strength properties of the material are F1t = F1c = 3F2c = 5F6 = 12F2t = 600 MPa. Determine the stress level, ?o, at which the laminae will fail according to the maximum stress theory. What is the failure mode?
Uploaded: 2023-10-29T09:24:29-08:00
Duration: 2 min 7 s
Channel: Supreeta N
Description: 1. A unidirectional lamina is under biaxial normal loading ?x = -2?y = 2?o at 45° to the fiber direction as shown below. The strength properties of the material are F1t = F1c = 3F2c = 5F6 = 12F2t = 600 MPa. Determine the stress level, ?o, at which the laminae will fail according to the maximum stress theory. What is the failure mode?

          1. A unidirectional lamina is under biaxial normal loading ?x = -2?y = 2?o at 45° to the fiber direction as shown below. The strength properties of the material are F1t = F1c = 3F2c = 5F6 = 12F2t = 600 MPa. Determine the stress level, ?o, at which the laminae will fail according to the maximum stress theory. What is the failure mode?

1. A unidirectional lamina is under biaxial normal loading ?x = -2?y = 2?o at 45° to the fiber direction as shown below. The strength properties of the material are F1t = F1c = 3F2c = 5F6 = 12F2t = 600 MPa. Determine the stress level, ?o, at which the laminae will fail according to the maximum stress theory. What is the failure mode?

Added by Martin B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

10/29/2023

Step 1

Using the transformation equations for plane stress, we get: σ1 = (σx + σy)/2 + (σx - σy)/2*cos(2*θ) + τxy*sin(2*θ) σ2 = (σx + σy)/2 - (σx - σy)/2*cos(2*θ) - τxy*sin(2*θ) τ12 = -(σx - σy)/2*sin(2*θ) + τxy*cos(2*θ) Substituting the given values, we get: σ1 = (2 Show more…

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A unidirectional lamina is under biaxial normal loading ̃σx = -2σy = 2σo at 45° to the fiber direction as shown below. The strength properties of the material are F1t = F1c = 3F2c = 5F6 = 12F2t = 600 MPa. Determine the stress level, σo, at which the laminae will fail according to the maximum stress theory. What is the failure mode?