00:01
Hello students, according to the given question we have to find the chebby chief's inequality.
00:13
So here they have given the values mean mu will be equal to 132 and standard deviation sigma is equal to 6 .4.
00:24
So in the a bit they have given 1 by 1 by k square will be equal to 56 % that means 1 by k square will be equal to 1 minus 0 .56, which will be equal to 0 .44.
00:42
Then k square will be equal to 1 is divided by 0 .44, then k will be equal to square root of 1 is divided by 0 .44, which is equal to 1 .5.
00:57
So by the chbby chips inequality, probability of mu minus k sigma less than x less than mu plus k sigma value will be equal to 1 minus 1 by k squared.
01:13
Here, mu minus k sigma will be equal to 132 minus 1 .5 into sigma value 6 .4.
01:24
So which is equal to 122 .4.
01:27
And mu plus k sigma will be equal to 132 plus 1 .5 into 6 .4 which will be equal to 141 .6.
01:41
Therefore at least 56 % measurements lies between 122 .4 and 141 .6 m.
02:05
Mhg.
02:08
In the b bit they have given mu minus k sigma value will be 119 .2...