00:01
Hello students, in this problem we want to find the deceleration required to avoid collision.
00:06
We know that v equal to x by t.
00:11
This is the expression for velocity.
00:14
Then the final displacement of the train equal to final displacement of the locomotive, that is, x f, t, which is equal to xfl.
00:28
Then we can write x.
00:31
I t plus half into v i t plus v f t into t which is equal to x i l plus vl t the initial position of the drain as our organ so initial position of the locomotive is d then we can write x i t which is equal to zero and x i which is equal to d then we can write 0 plus half into vit plus vl into t which is equal to d plus vl into t from this we can find an equation for t as that is t equal to d divided by half into v i t minus v l l just substitute all the values here, that is 6 .76 divided by half into 161 into 0 .277 divided by 1 minus 29 into 0 .277 divided by 1.
01:55
On calculation, we get t as t equal to 36 .8 second.
02:05
Now, the deceleration required to avoid collision, that is, a can be written as a equal to vft minus vit divided by t...