In parts (A)-(C), find the indicated quantity for y = f(x) = 6 - x^2. (A) (f(2) - f(1)) / ((2) - (1)) =
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To do this, we can use the power rule for derivatives: (d/dx)(a^x) = a^x * ln(a), where a is a constant. So, the derivative of 6 - 2^x is: f'(x) = 0 - (2^x * ln(2)) Now, we need to find the value of the derivative at x = 1: f'(1) = - (2^1 * ln(2)) f'(1) = Show more…
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