Question

Same as the previous problem (lens to retina 2.5 cm, object at $s = \infty$), except for a far-sighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?

Name: Same as the previous problem (lens to retina 2.5 cm, object at s = ∞), except for a far-sighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?
Uploaded: 2023-08-25T18:49:48-08:00
Duration: 2 min 38 s
Channel: Lottie Adams
Description: Same as the previous problem (lens to retina 2.5 cm, object at s = ∞), except for a far-sighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?

          Same as the previous problem (lens to retina 2.5 cm, object at $s = \infty$), except for a far-sighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?

Same as the previous problem (lens to retina 2.5 cm, object at s = ∞), except for a far-sighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?

Added by David T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Lottie Adams

08/25/2023

Step 1

5 cm. This is the distance from the lens to the screen where the image is formed. Show more…

Show all steps

Thanks for your feedback!

Lens to retina 2.5 cm. Object at s = o). Except for a farsighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now, what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?