Let A and B be two events, with probabilities P(A) = 0.6, and P(B) = 0.2. Calculate the following probabilities: P(A0), P(A ∩ B), P(A ∪ B), P(A|B), P(B|A), if: (1) A and B are mutually exclusive (disjoint). (2) A and B are independent.
Added by Aljoharah F.
Step 1
In other words, P(A ∩ B) = 0. Now, let's calculate the other probabilities: P(A0) = 1 - P(A) = 1 - 0.6 = 0.4 (A0 is the complement of A, meaning the event A does not occur) P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 0.6 + 0.2 - 0 = 0.8 (A ∪ B means either A or B or Show more…
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