00:01
So in this one we have matrix a as 1 to 512.
00:09
Matrix b1 as negative 4, negative 16, matrix b2 as 22, matrix b3 as 06, and matrix b4 as 1, negative 7.
00:32
In part a, we want a inverse, and there is an inverse because it's a 2x2 matrix.
00:36
We take 1 times the determinant.
00:38
12 times 1 is 12.
00:40
That's this column, or that row diagonal, minus the other diagonal.
00:47
That's 10 times we flip the main diagonal, 12 and 1, and change the signs on the other diagonal.
00:54
And we end up with an inverse of 6, negative 1, negative 5, 1.
01:01
And one half.
01:04
So if we take a inverse times b1, or 6, negative 1, negative 5, halves, 1 half times negative 4, negative 16, that gives us a solution matrix of 6 times negative 4 plus negative 1 times negative 16 or negative 8 and negative 5 halves times negative 4 plus 1 1ā2 negative 16 which is positive 2 and if we repeat that process for a inverse b2 we end up with 10 negative 4 inverse 3 6 negative 3 a now if we use the coefficient matrix, for b, we end up with the matrix...