We are given P(B) = 0.52, P(A|B) = 0.12, and P(A|B') = 0.29. We can find P(B') as 1 - P(B) = 1 - 0.52 = 0.48.
Now, we can find P(A):
P(A) = 0.12 * 0.52 + 0.29 * 0.48 = 0.0624 + 0.1392 = 0.2016
So, the probability that a randomly selected person is a heavy
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