00:01
All right, so we're looking at chapter 2, section 2, question 52, and what i'm going to do is for row 2, i'm going to subtract it from row 1, and that'll produce the following results.
00:24
1, 2, 2, 4, 6, 0 ,0, 1, 2, 2, 3, and so that column on the, my first column zeroed out.
00:38
Second column.
00:39
However, we see redundancy.
00:43
So i'm going to subtract row three from row to zero out my third row.
00:49
I'll now have one, two, two, two, four, six, zero, one, two, two, three, zero, zero, zero, zero, zero, equals you.
01:07
All right.
01:11
Next to find the special solution, we will first find reduced row form r so for row one i'm going to subtract it from two of row two that's looking at you okay so we have one two zero zero zero zero one two three zero zero zero zero zero 0 equals 1 or equals r where x sub 1, x sub 2, x sub 3, and x of 4, and x sub 5 are as follows.
02:13
X sub 1 equals negative 2, x up 2, x sub 2.
02:19
It's an element of all real numbers...