00:01
Hi from the question given that b is equal to matrix minus 3 3 minus 1 2 and the matrix a is equal to 1 4 14 10 10 1 0 minus 3 0 1 3 0 1 3 4 minus 2 minus 2 minus 2 minus 3 4 4 minus 2 minus 1 minus 1 minus 1 minus 1 minus 1 minus 1 minus 7 minus 12.
00:39
So here x tends to a .x.
00:43
To find b is the range of linear transformation.
00:46
So first write the augmented matrix a comma b.
00:52
So this imply 1, 4, 14, 10, 1, 0, 0, 3, 3, 4, 4, 4, 10, 1, 2, minus 3, 0, 1, 3, 4, minus 2, 2, 1, 4, minus 2, minus 1, minus 7, minus 12, augmented form minus 3, 3, minus 1, 2.
01:31
Now perform the road reduction method to find the rank.
01:37
So first perform r2 implies r2 minus r1.
01:45
So the matrix became 1, 4, 14, 10, 0.
01:55
Minus 4 minus 12 minus 13 0 1 3 4 minus 2 minus 1 minus 2 minus 1 minus 1 2 now again perform the row reduction r 4 implies r 4 plus 2 r1.
02:28
Therefore the above matrix became 1, 4, 14, 10, 0, minus 4, minus 12, minus 13, 0, 1, 3, 4, 0, 7, 7, 21, 21, 8 with augmented form, minus 3, 6, minus 1, minus 4.
02:55
Now again perform the row operation...