Question

Let C(x) = 11x + 7 be the cost (in hundreds of dollars) to produce x units of a certain commodity, and the R(x) = ?x^2 + 19x be the revenue (in hundreds of dollars) from the sale of x units of that commodity. How many units must the manufacturer of the commodity produce and sell in order to maximize their profit? What is that maximum profit? Note that profit can be computed by subtracting cost from revenue.

Name: let cx 11x 7 be the cost in hundreds of dollars to produce x units of a certain commodity and the rx x2 19x be the revenue in hundreds of dollars from the sale of x units of that commodity h 79598
Uploaded: 2023-06-10T11:55:58-08:00
Duration: 1 min 13 s
Channel: Donna Densmore
Description: let cx 11x 7 be the cost in hundreds of dollars to produce x units of a certain commodity and the rx x2 19x be the revenue in hundreds of dollars from the sale of x units of that commodity h 79598

          Let C(x) = 11x + 7 be the cost (in hundreds of dollars) to
produce x units of a certain commodity, and the R(x) = ?x^2 + 19x
be the revenue (in hundreds of dollars) from the sale of x units of
that commodity. How many units must the manufacturer of the
commodity produce and sell in order to maximize their profit? What
is that maximum profit? Note that profit can be computed by
subtracting cost from revenue.

Added by Victor F.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Donna Densmore

06/10/2023

Step 1

To find the maximum profit, we need to find the point where revenue equals cost. This is because any units produced and sold beyond this point will result in a decrease in profit. Show more…

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Let C(x) = 11x + 7 be the cost (in hundreds of dollars) to produce x units of a certain commodity, and the R(x) = ?x^2 + 19x be the revenue (in hundreds of dollars) from the sale of x units of that commodity. How many units must the manufacturer of the commodity produce and sell in order to maximize their profit? What is that maximum profit? Note that profit can be computed by subtracting cost from revenue.