Question

Let E and F be two events in S with P(E) = 0.35, P(F) = 0.58, and P(E cap F) = 0.2. Find P(EC cap F) and P(EC cap FC). P(EC cap F) = P(EC cap FC)=

          Let E and F be two events in S with P(E) = 0.35, P(F) = 0.58, and P(E cap  F) = 0.2. Find P(EC cap  F) and P(EC cap  FC). 
P(EC cap  F)   =
P(EC cap  FC)=
        

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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Let E and F be two events in S with P(E) = 0.35, P(F) = 0.58, and P(E cap F) = 0.2. Find P(EC cap F) and P(EC cap FC). P(EC cap F) = P(EC cap FC)=
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Transcript

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00:01 In this problem, we are given that there are two events e and f, and the probability of these two events are given as well.
00:08 So probability of event e is given as 0 .45, probability of f, that is equal to 0 .63, and probability of e union f, well, that's given as 0 .87.
00:23 And we are required to find out the probability of e intersection f and probability of e.
00:30 Intersection f complement.
00:33 So here we simply use this formula and let's just replace a and p with e and f respectively.
00:39 So doing that we would get the probability of e union f as probability of e plus probability of f minus probability of e intersection f so when we plug in the values we would get 0 .87 equal to 0 .45 plus 0 .63 minus probability of e intersection f...
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