Question

Let $f(x) = \frac{2}{x - 4}$. Then according to the definition of derivative $f'(x) = \lim_{t \to x}$ (Your answer above and the next few answers below will involve the variables $t$ and $x$.) The expression inside the limit simplifies to a simple fraction with numerator = and denominator = We can cancel the factor appearing in the denominator against a similar factor appearing in the numerator leaving a simpler fraction with numerator = and denominator = Taking the limit of this fractional expression gives us $f'(x) = $

          Let $f(x) = \frac{2}{x - 4}$. Then according to the definition of derivative
$f'(x) = \lim_{t \to x}$
(Your answer above and the next few answers below will involve the variables $t$ and $x$.)
The expression inside the limit simplifies to a simple fraction with
numerator = 

and denominator = 
We can cancel the factor appearing in the denominator against a similar factor appearing in
the numerator leaving a simpler fraction with
numerator = 
and denominator = 
Taking the limit of this fractional expression gives us
$f'(x) = $

$Let f(x) = (2)/(x - 4). Then according to the definition of derivative f'(x) = limt → x (Your answer above and the next few answers below will involve the variables t and x.) The expression inside the limit simplifies to a simple fraction with numerator = and denominator = We can cancel the factor appearing in the denominator against a similar factor appearing in the numerator leaving a simpler fraction with numerator = and denominator = Taking the limit of this fractional expression gives us f'(x) =$

Added by Nancy B.

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