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Let $f(x) = (x - 8)^2$ Find a domain on which $f$ is one-to-one and non-decreasing. Find the inverse of $f$ restricted to this domain. $f^{-1}(x) = $

          Let $f(x) = (x - 8)^2$
Find a domain on which $f$ is one-to-one and non-decreasing.
Find the inverse of $f$ restricted to this domain.
$f^{-1}(x) = $
        
Let f(x) = (x - 8)^2
Find a domain on which f is one-to-one and non-decreasing.
Find the inverse of f restricted to this domain.
f^-1(x) =

Added by Vicente J.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Let f(x) = (x - 8)^(2) Find a domain on which f is one-to-one and non-decreasing. Find the inverse of f restricted to this domain. f^(-1)(x) = Question Help: Video Message instructor Let f(x) = (x - 82) Find a domain on which f is one-to-one and non-decreasing. Find the inverse of f restricted to this domain. f^(-1)(x) = Question Help: Video Message instructor Submit Question
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Transcript

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00:01 So in this problem, the first thing we want to do is we want to find the entire domain on this function that is one -to -one so that it's non -decreasing.
00:09 Well, we can have f -f x is equal to x -square minus 9.
00:12 Well, let's think about what this graph would look like.
00:14 It's at x squared, so that's our typical parabola, but it got shifted down 9.
00:19 So our graph would look something like this.
00:21 Well, we want the part of our graph for which is non -decreasing, which means it would start here at the vertex when x is 0 and then be anything greater.
00:30 Therefore, the domain in interval notation, remember we're talking from when x is zero up until it goes to infinity.
00:37 So in, here we go, here's domain.
00:40 So in terms of intonation, our domain, we would have to restrict it to zero up until infinity.
00:46 So that's the first part.
00:48 Now, the second part says to find the inverse of f restricted to that domain...
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