Let $f(x) = 6x^2 + 18x + 2$. a. What is the vertex of $f(x)$? b. What is the $y$-intercept?
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To find the vertex of a quadratic function in the form f(x)=ax^2+bx+c, we can use the formula x = -b/(2a) to find the x-coordinate of the vertex. In this case, a=6 and b=18. So, x = -18/(2*6) = -18/12 = -3/2. Now, substitute x=-3/2 back into the original Show more…
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