Question

Let $f(x) = x^2 - 9$ and $g(x) = 2x - 4$. Find the value, if possible. (If not possible, enter IMPOSSIBLE.) $(f \cdot g)(-3)$ $(f \cdot g)(-3) = $

          Let $f(x) = x^2 - 9$ and $g(x) = 2x - 4$. Find the value, if possible. (If not possible, enter IMPOSSIBLE.)
$(f \cdot g)(-3)$
$(f \cdot g)(-3) = $

Let f(x) = x^2 - 9 and g(x) = 2x - 4. Find the value, if possible. (If not possible, enter IMPOSSIBLE.)
(f · g)(-3)
(f · g)(-3) =

Added by Sara I.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Amy Jiang

07/07/2020

Step 1

(f*g)(x) = f(x) * g(x) (f*g)(x) = (x^2 - 9) * (2x - 4) (f*g)(x) = 2x^3 - 4x^2 - 18x + 36 Now, substitute x = -3 into the expression: (f*g)(-3) = 2(-3)^3 - 4(-3)^2 - 18(-3) + 36 (f*g)(-3) = 2(-27) - 4(9) + 54 + 36 (f*g)(-3) = -54 - 36 + 54 + 36 (f*g)(-3) = Show more…

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Let f(x)=x^(2)-9 and g(x)=2x-4. Find the value, if possible. (If not possible, enter IMPOSSIBLE.) (f*g)(-3) (f*g)(-3)= Let f() = 2 - 9 and g() = 2x -- 4. Find the value, if possible. (If not possible, enter IMPOSSIBLE.) (f.g)(-3) (f.g)(-3)=