let G be a finite group of order n, let m be an integer such that gcd(m,n)= 1, show that if g∈G and g^m= e, then g=e
Added by Richard R.
Step 1
We have a finite group \( G \) with order \( n \), and an element \( g \in G \) such that \( g^m = e \), where \( e \) is the identity element of the group. We also know that \( \gcd(m, n) = 1 \). Show more…
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