00:02
Hi here for the given question.
00:04
We are given that you is equal to minus 2 0 4 v is equal to 3 minus 1 6 and w is equal to 2 minus 5 and 5.
00:15
Now here we need to calculate the distance between minus 3 u and v plus 5 w.
00:27
So here in our case in order to calculate the distance between this we have here the value of minus 3 u minus v plus 5 times w which is equal to minus 3 multiplied with minus 2 0 4 minus v which is 3 1 minus 6 3 minus 1 plus 6 minus 5 times 2 minus 5 minus 5.
00:57
So here in our case now on simplifying this here we can say that value of 3 u minus v plus 5 times w equals to minus 7 26 and 7.
01:09
So here the value of the distance v is equal to norm of this value.
01:15
So here we have under root of minus 7 square plus 26 square plus 7 square.
01:22
So this is equal to under root of 774.
01:25
So here the value of this distance v is equal to 3 times under root of 86.
01:33
So this is the first part solution now here further for the next part.
01:38
We need to calculate what is the value of u dot v multiplied with w.
01:51
So first of all, we will calculate the dot product.
01:53
So here the dot product of u and v will be minus 2 multiplied with 3 plus 0 multiplied with minus 1 plus 4 multiplied with 6 and the value is again multiplied with w.
02:04
So here we have 18 times w.
02:06
So this is equal to 18 multiplied with 2 minus 5 and minus 5.
02:11
So here this value is equal to 36 minus 90 and minus 90.
02:15
Now further we need to calculate the value of minus 5 v plus w.
02:20
So this is equal to minus 5 times 3 minus 1 and 6 plus 2 minus 5 and minus 5.
02:28
So here by calculating this value here, we can see that the value of minus 5 v plus w is equal to minus 15 5 comma minus 30 plus 2 comma minus 5 comma minus 5.
02:46
So this is equal to minus 13 0 and 35.
02:54
This is negative 35.
02:56
So here in our case now, we need to take the cross product of this to need to find the cross product of minus 5 v plus w with u dot v multiplied with w.
03:07
So this is equal to cross product of minus 13 0 minus 35 and here we have 36 minus 90 and minus 90.
03:20
So after taking the cross product and simplifying this here, we can see that we have this value equals to minus 3 ,150 comma minus 2 ,430 comma 1170.
03:34
So here this is the solution for the first part.
03:38
We need to calculate what is the value of projection of u from v and v onto u.
03:49
So here for the second part, we are given that the value of u is equal to 0 1 3 minus 6 and v is equal to minus 1 1 2 and 2.
03:59
Now we need to calculate the value of the projection.
04:02
So here in our case the formula to calculate the projection of v on u is equal to u v divided by norm of vector v multiplied with v.
04:12
So here in our case the dot product of u and v is equal to minus 5 and the norm of v square is equal to 10...