00:01
In this question, we're given probability of event e is 0 .2, probability of event f is 0 .3.
00:07
And probability of f in the set e is 0 .1.
00:10
Now, let's draw the event diagram.
00:15
So over here is event e.
00:18
Over here is event f.
00:20
Now, probability of f in the set e is in common between these two events is 0 .1.
00:25
So over here is 0 .1.
00:27
Now, we know that the entire probability of e here, the entire thing, is 0 .2.
00:33
And so to find over here, it's just going to take 0 .2 minus 0 .1, and so we get 0 .1 over here.
00:44
Now, how about over here, probability of f is 0 .3? so to get over here, that's f only.
00:54
We take 0 .3 minus 0 .1, so we'll get 0 .2.
00:59
Now, if you were to add up this individual's probability is 0 .4, so whatever that is outside of these two set is going to be 1 minus 0 .4 and that will be 0 .6.
01:11
Now, part a, we want to find the conditional probability of e given f complement has already occurred.
01:21
So using bas theorem, the formula will be probability of e intersect f complement divided by probability of f complement...